Senin, 07 Februari 2011

Subnetting

If an owner of a class B IP address such as requiring more than one network ID then it must apply with Internic to get a new IP address. However, very limited supply of IP addresses because a lot of proliferation of sites on the Internet. To overcome this timbulah a technique to reproduce the network ID of an existing network. This is called subnetting, where most of the host ID sacrificed for use in making additional network ID. For instance, for example in the class B network ID 130.200.0.0 with a subnet mask of 255.255.224.0 where the third octet diselubung with 224. then can be calculated with the formula 256-224 = 32. then the group of subnets that can be used is a multiple of 32, 64, 128, 160, and 192. Thus groups of IP addresses that can be used are: 130.200.32.1 through 130.200.63.254 130.200.64.1 through 130.200.95.254 130.200.96.1 up to 130 200 127 254 130.200.128.1 through 130 200 159 254 130.200.160.1 through 130 200 191 254 130.200.192.1 through 130 200 223 254 Or would be easier with a good formula to determine subnet and host number persubnet.Jumlah subnet = 2n-2, n = number of bits hidden The number of hosts persubnet = 2N-2, N = number of bits is not veiled For example, such a subnet has a network address with a subnet mask of 193.20.32.0 255 255 255 224. Then: The number of subnets is 6, because of network address 193.20.32.0 by considering the number of the first octet is 193, then it can be in the know are in class C. with regard Subnet 255 255 255 224 or 11111111.11111111.11111111. 11100000 can be seen that three-bit host ID diselubung, in order to get n = 3 and obtained: the number of subnets = 23-2 = 6. As for the number of hosts persubnet is 30, is obtainable from 5 bits that are not hidden, then N = 5 and will be obtained: the number of hosts per subnet = 25-2 = 30. Bit is a bit shrouded in represented by number 1, while bits are the bits that are not shrouded in representing the number 0.

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